Answer:
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Answer: £14378
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = £11000
n = 1 because it was compounded once in a year.
For the first 3 years,
r = 3.9% = 3.9/100 = 0.039
Therefore,
A = 11000(1+0.039/1)^1 × 3
A = 11000(1.039)^3
A = $12338
The new principal is 12338
For the next 4 years,
A = 12338(1.039)^4
A = 14378
Answer:
<h2>
x= 2/3</h2>
Step-by-step explanation:
x−6 = 4(2−3x)−8x
Rearrange terms
x-6= 4(-3x+2)-8x
Distribute
x-6= -12x+8-8x
Combine Like Terms
x-6= -20x+8
21x-6= 8
Isolate x
21x= 8+6
21x=14
x= 14/21
Simplify
x=2/3
Your suppose to take the order pair you got and subsitute it in both of the equations. The chart has the y and x on one side and a number on the other. Treat it like an algebraic equation and try to see if when you subsitute the x and y with the order pair given you get the number on the other side of the equation. For example x + 3y = 6 once subsituted with the order pair looks like 3 + 3(1) = 6. From there you do one step at time until finally you get 6 = 6 which tells you that (3,1) is a solution for this equation. Now you have to find out if the ordered pair works for both of the equations not just one since it said "given system". Hope I explained it clearly enough :)
This is an arithmetic sequence
f(1) = 7(0) -10 = -10
f(2) = 7(1) -10 = -3
f(3) = 7(2) -10 = 4
f(4) = 7(3) -10 = 11
