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ra1l [238]
3 years ago
13

Find the unknown angle measure by solving for the given variable.

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

A triangle is 180°. So you can do:

3.2n + 6.4n + 2.4n = 180   Simplify

12n = 180

n = 15   Now that you know the value of n, you can plug it into each individual angle/equation

∠X = 3.2n    plug in 15 for n

∠X = 3.2(15)

∠X = 48°

∠Y = 6.4(15)

∠Y = 96°

∠Z = 2.4(15)

∠Z = 36°

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Help Me On These Please
RoseWind [281]
#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term

#2 has zero like terms. 15 has no variable, and the other terms have different variables.

#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.

#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
7 0
3 years ago
two angles form a straight angle. what is the one angle measures 89°. what is the measure of the other angle?
ICE Princess25 [194]
A straight line is = to 180 degrees (straight angle) so the formula would be
X+89=180
subtract the 89 from both sides and you get x=91
so the other angle is 91 degrees
4 0
3 years ago
Read 2 more answers
Marty was renting a boat and wanted to get the best plan. Rental plan A charges a fee of
harina [27]

The system of equations that represent the situation are as follows;

  • C = $50 + $25h

  • C = $10 + $35h.

According to the question;

  • Mary was trying to rent a boat and wanted to get the best plan.

  • Let C = Charged fees

  • and h = hours of rental

For Plan A:

  • Rental plan A charges a fee of
  • $50 plus $25 per hour.

  • C = $50 + $25h

For Plan B:

  • Plan B charges a fee of $10 plus $35 per hour.

  • C = $10 + $35h.

Read more on rental charges;

brainly.com/question/1503197

6 0
2 years ago
Read 2 more answers
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
If Lana deposits $500 into a savings account that gains simple interest at
Oksana_A [137]

Answer:

10 years

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 2%/100 = 0.02 per year,

then, solving our equation

t = 100 / ( 500 × 0.02 ) = 10

t = 10 years

The time required to

accumulate simple interest of $ 100.00

from a principal of $ 500.00

at an interest rate of 2% per year

is 10 years.

3 0
3 years ago
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