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3 years ago

30-60-90 triangle ... find the value of x?

Mathematics

2 answers:

ipn [44]3 years ago

7 0

12x square root is 3

Citrus2011 [14]3 years ago

3 0

24/2 = 12
12 x (square root of 3)

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BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh

bekas [8.4K]

Answer:

D. x²/1953² + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953² + y²/ 1466² = 1

8 0

3 years ago

When estimated, is 6.2-4.96 greater or less than 1?

pogonyaev

6.2 - 4.96 = 1.24 > 1
1.24 is greater than 1.

7 0

4 years ago

.......................answer

irakobra [83]

Answer:

d. 12xy

Step-by-step explanation:

The + signs separate terms.

3 0

3 years ago

The Falcons had 3 fewer than twice as many Bears players. If the Falcons had 11 players, how many players were on the Bears?

Dmitry [639]

Subtraction, 11-3 is 8
Ps:trick question

3 0

2 years ago

Beatrice built about 1/3 of a sandcastle. Linda built 4/7 of the same castle. What fraction of the sandcastle did they build tog

wlad13 [49]

Answer

Find out the what fraction of the sandcastle did they build together .

To prove

Let us assume that the fraction of the sandcastle they build together be x .

As given

$Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.$

$Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.$

Than the equation becomes

$x = \frac{1}{3} +\frac{4}{7}$

L.C .M of (3,7) = 21

solving

$x = \frac{7 + 3\times4}{21}$

$x = \frac{19}{21}$

Therefore the fraction of the sandcastle did they build together be

$x = \frac{19}{21}$

Hence proved

4 0

3 years ago