Answer:
train A=38mph train B=44mph
Step-by-step explanation:
Setting up a table:
s t d
A x 190/x 190
B x+6 220/x+6 220
Train A was 6mph slower as shown in the table, so to make it easier, train a is identified as x, train b would be x+6
Their distances are put in their respective column.
You find time from distance divided by speed.
So time would be written as such.
Since you know they take the same amount of time, for the equation, you connect them with an equal sign. Cross multiply to something like:
190(x+6)=220x
190x+1140=220x
1140=30x
x=38
You plug this in and get the speed for train A as 38, and train B as 44.
Hope this helps ^^
