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ale4655 [162]
3 years ago
8

Item 14 Evaluate 2y+x2÷4 when x=6 and y=4. When x=6 and y=4, 2y+x2÷4=

Mathematics
2 answers:
Maru [420]3 years ago
5 0
11 you need to use pemdas then multiply by the variable
mart [117]3 years ago
3 0

Answer: The answer is 5

Step-by-step explanation:2(4)+(6)2/4=5

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What is x?: 22+54x= -20 + 60x
DENIUS [597]
Answer:
x = 7

Explanation:
We are given
22 + 54x = -20 + 60x

We can add 20 on both sides using the Addition Property of Equality
42 + 54x = 60x

Subtract both sides by 54x using the Subtraction Property of Equality
42 = 6x

Divide both sides by 6 using the Division Property of Equality
x = 7
8 0
2 years ago
Exercise 11.21) Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad ba
stiv31 [10]

Answer:

Step-by-step explanation:

Hello!

The researcher suspects that the battery life between charges for the Motorola Droid Razr Max differs if its primary use is talking or if its primary use is for internet applications.

Since the means for talk time usage (20hs) is greater than the mean for internet usage (7hs) the main question is if the variance in hours of usage is also greater when the primary use is talk time.

Be:

X₁: Battery duration between charges when the primary usage of the phone is talking. (hs)

n₁= 12

X[bar]₁= 20.50 hs

S₁²= 199.76hs² (S₁= 14.13hs)

X₂: Battery duration between charges when the primary usage of the phone is internet applications.

n₂= 10

X[bar]₂= 8.50

S₂²= 33.29hs² (S₂= 5.77hs)

Assuming that both variables have a normal distribution X₁~N(μ₁;σ₁²) and X₂~N(μ₂; σ₂²)

The parameters of interest are σ₁² and σ₂²

a) They want to test if the population variance of the duration time of the battery when the primary usage is for talking is greater than the population variance of the duration time of the battery when the primary usage is for internet applications. Symbolically: σ₁² > σ₂² or since the test to do is a variance ratio: σ₁²/σ₂² > 1

The hypotheses are:

H₀: σ₁²/σ₂² ≤ 1

H₁: σ₁²/σ₂² > 1

There is no level of significance listed so I've chosen α: 0.05

b) I've already calculated the sample standard deviations using a software, just in case I'll show you how to calculate them by hand:

S²= \frac{1}{n-1}*[∑X²-(∑X)²/n]

For the first sample:

n₁= 12; ∑X₁= 246; ∑X₁²= 7240.36

S₁²= \frac{1}{11}*[7240.36-(246)²/12]= 199.76hs²

S₁=√S₁²=√199.76= 14.1336 ≅ 14.13hs

For the second sample:

n₂= 10; ∑X₂= 85; ∑X₂²= 1022.12

S₂²= \frac{1}{9}*[1022.12-(85)²/10]= 33.2911hs²

S₂=√S₂²=√33.2911= 5.7698 ≅ 5.77hs

c)

For this hypothesis test, the statistic to use is a Snedecors F:

F= \frac{S_1^2}{S_2^2} *\frac{Sigma_1^2}{Sigma_2^2} ~~F_{n_1-1;n_2-1}

This test is one-tailed right, wich means that you'll reject the null hypothesis to big values of F:

F_{n_1-1;n_2-1; 1-\alpha }= F_{11;9;0.95}= 3.10

The rejection region is then F ≥ 3.10

F_{H_0}= \frac{199.76}{33.29} * 1= 6.0006

p-value: 0.006

Considering that the p-value is less than the level of significance, the decision is to reject the null hypothesis.

Then at a 5% level, there is significant evidence to conclude that the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for talk is greater than the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for internet applications.

I hope this helps!

8 0
2 years ago
What conclusion can be determined from the dot plot below?
EleoNora [17]

Answer:

The number of observations is 15.

3 0
3 years ago
Read 2 more answers
Which points are located in the third quadrant?
8090 [49]

Answer: for example (-2,-2), (-3,-6), and (-8,-10)

Step-by-step explanation: every point in the third quadrant is both negative.

8 0
2 years ago
The bar diagram represents 24 hours in one day and shows a mark at 30%. If you sleep 30% of the day, how many hours do you sleep
Sedbober [7]
30% = 3/10

Number of hours you sleep = 24hours × 3/10
= 24hours ÷ 10 × 3
= 2.4hours × 3
= 7.2hours

Hope this helps! :)
4 0
2 years ago
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