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ale4655 [162]
3 years ago
8

Item 14 Evaluate 2y+x2÷4 when x=6 and y=4. When x=6 and y=4, 2y+x2÷4=

Mathematics
2 answers:
Maru [420]3 years ago
5 0
11 you need to use pemdas then multiply by the variable
mart [117]3 years ago
3 0

Answer: The answer is 5

Step-by-step explanation:2(4)+(6)2/4=5

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Find area of triangle whose base is 2 √3 and height is 3 √3
Lera25 [3.4K]
Area of a triangle = base times height
A = 2√3 times 3√3
A = 18
The answer is 18
Hope that helps
7 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
Round 3.6481 to the hundredths place (two decimal places).To the right
bekas [8.4K]
The correct answer would be 3.65.
4 0
3 years ago
Elmer sees a flying saucer. The radius of the flying saucer is 17 feet. What is the area of the flying saucer (use 3.14 for pi a
sergiy2304 [10]

Answer:

Area of the flying saucer = 907.46 ft^2

Step-by-step explanation:

The Flying saucer is in the shape of a circle.

Radius= 17 feet

Area of the circular flying saucer= \pi *r*r

                                                                         :\pi =\frac{22}{7} =3.14

                                  Area= 3.14*17*17

                                     

  Area of the flying saucer =3.14*289\\\\    =907.46 ft^2

So, the area of the flying saucer is 907.46 ft^2

8 0
4 years ago
What is the surface area of the pyramid?
-Dominant- [34]

Answer:

166 square units

Step-by-step explanation:

Let’s find the area of the shapes that in the net.

First, we can see two of the triangles have a base of 2 and a height of 13. The formula for surface area of a triangle is bh÷2. (13x2)÷2=13. Since there are two triangles, we multiply 13 by 2 and get <u><em>26</em></u>.

Second, we can see two of the triangles have a base of 10 and a height of 12. (10x12)÷2=<u>60.</u> Since there are two triangles, we multiply 60 by 2 and get <u>120</u>.

Third, we can see a rectangle has a base of 10 and a height of 2. The formula for surface area of a rectangle is bh. 10x2=<u>20</u>.

Last, we add up all the areas:

20+120+26=166.

6 0
3 years ago
Read 2 more answers
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