Ask question

Ask question

All categories

3 years ago

11

A right rectangular prism has a volume of 54 cubic inches. If the height of the prism is 9 inches, what is the area of the base

of the prism?

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

9

Step-by-step explanation:

area of base * height = 54

area of base * 9 = 54

You might be interested in

Point A (-3,-5) and point M is at (-1,-7) what are the coordinates point of be

Sindrei [870]

Answer: B = (1,-9)

Step-by-step explanation:

$x_M=\frac{x_A+x_B}{2} \\\\y_M=\frac{y_A+y_B}{2} \\\\\\x_B = 2x_M-x_A=2(-1)-(-3)=1\\\\y_B = 2y_M-y_A=2(-7)-(-5)=-9\\$

3 0

4 years ago

A. Beneath each problem, explain what you would do if you were showing how to solve the problem using a number line. Then state

kodGreya [7K]

Answer:

-1 is the first answer of question

-8 is the answer of second question

6 0

3 years ago

Read 2 more answers

What is the best approximation for the area of a circle with a diameter of 19 meters?

sammy [17]

283.4 thats what my quiz said

3 0

4 years ago

Please help, I’ll mark your answer as brainliest.

Brrunno [24]

Answers:

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\$

========================================================

Work shown for part 1

$f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\$

----------------------------------

Work shown for part 2

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\$

6 0

2 years ago

7th grade math help me plzzz

gladu [14]

Answer:

-3+4 or 4+-3

Step-by-step explanation:

Take both numbers than put together plz mark me brainiest

3 0

4 years ago

Read 2 more answers