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2 years ago

For the given function, x can have what value?

Mathematics

1 answer:

Lyrx [107]2 years ago

5 0

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

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2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

2 years ago

Rearrange the standard form of the equation below into y = mx + b by isolating y. <br> 5x − 2y = 6

Minchanka [31]

Answer:

y = $\frac{5}{2}$ x - 3

Step-by-step explanation:

5x - 2y = 6 ( subtract 5x from both sides )

- 2y = - 5x + 6 ( divide through by - 2 )

y = $\frac{5}{2}$ x - 3 ← in slope- intercept form

5 0

2 years ago

Can someone help me with this

ludmilkaskok [199]

Answer:

Step-by-step explanation:

1/2r +1/2= -2/7r -29/7 Subtracting 1/2 from both sides

1/2r +1/2 - 1/2= -2/7r -29/7- 1/2

1/2r = -2/7r - 29(2)-7/14

1/2r = -2/7r -65/14

3 0

2 years ago

Is 5x +4 equivalent to 5(x-1) +9

HACTEHA [7]

$5x+4=5(x-1)+9\\5x+4=5x-5+9\\4=4\\$

Yes, it does

8 0

3 years ago

Everyday on his way to his part time job, Landon stops by Starbucks for a Caramel Frappuccino and a cake pop. He gets another cu

il63 [147K]

Answer:

If a week is 7 days then a Caramel Frappuccino cost 2 dollars (unrounded cost 1.99285714)

Step-by-step explanation:

6 0

2 years ago