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3 years ago

For the given function, x can have what value?

Mathematics

1 answer:

Lyrx [107]3 years ago

5 0

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

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Please help! Find the length of segment AB to the nearest hundredth.

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3 years ago

Alexis wants to make a paperweight at pottery class. He designs a pyramid-like model with a base area of 100square centimeters a

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Answer:

The density of the material must be at least 1.5 g/cm³.

Step-by-step explanation:

The volume for a pyramid is given by the following formula:

V = (1/3)*Abase*h

Where V is the volume, Abase is the base area and h is the height. For Alexis's pyramid, we have:

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3 years ago

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If x2=18x+y and y2=18y+x, then find the value of root

mezya [45]

Answer:

$\sqrt{x^2+y^2+1}=18$

Step-by-step explanation:

We are given:

$x^2=18x+y\qquad\qquad[1]$

$y^2=18y+x\qquad\qquad[2]$

Subtracting [1] and [2]:

$x^2-y^2=18x+y-(18y+x)$

Operating:

$x^2-y^2=18x+y-18y-x$

Recall:

$x^2-y^2=(x-y)(x+y)$

Substituting:

$(x-y)(x+y)=18x+y-18y-x$

Rearranging:

$(x-y)(x+y)=18x-18y-(x-y)$

$(x-y)(x+y)=18(x-y)-(x-y)$

Dividing by x-y (recall x≠y):

$x+y=18-1=17$

$x+y=17\qquad[3]$

Now we add [1] and [2]:

$x^2+y^2=18x+y+18y+x$

Rearranging:

$x^2+y^2=18x+18y+x+y$

$x^2+y^2=18(x+y)+(x+y)$

$x^2+y^2=19(x+y)$

Substituting from [3]

$x^2+y^2=19*17=323$

Adding 1:

$x^2+y^2+1=324$

Taking the square root:

$\sqrt{x^2+y^2+1}=\sqrt{324}=18$

Thus:

$\mathbf{\sqrt{x^2+y^2+1}=18}$

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