Determine which postulate can be used to prove that the triangles are congruent. If it

Mathematics

1 answer:

Misha Larkins [42]2 years ago

6 0

Answer:

not possible

Step-by-step explanation:

You are told that one side of each triangle is congruent, and we know that vertical angles are congruent, therefore you have SA. SA does not determine similarity, so it is not possible with the amount of information given.

You might be interested in

F(x)=2x-1 g(x)=3 h(x)=x²+1 Compute the following: Find f(3)

inn [45]

If f(x)=2x-1 just plug in the 3 where x is. So it would be 2(3)-1=5

6 0

2 years ago

28 percent of 63 is what

baherus [9]

The answer is 17.64

4 0

3 years ago

Read 2 more answers

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,