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noname [10]
3 years ago
7

The distance around a circular dance hall room is 135 feet. What is the longest distance around the dance hall?

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0

Answer:

42.95 feet

Step-by-step explanation:

In this question, we are tasked with calculating the distance around the dance hall that is the greatest.

Now, to answer this, we must have at the back of our mind that the dance hall is circular in shape. Thus, the greatest distance that could arise is the distance from one edge of the dance hall to the other end of the dance passing exactly through the center of the dance hall.

This distance described above is the diameter of the dance hall.

Notice we were given a length in the question? This length refers to the circumference around the circular dance hall.

Reframing then question, we were just told to calculate the diameter of a circle given the circumference of the circle.

Mathematically, circumference C of a circle = 2 * pi * r

Recall, mathematically also 2r = D

so we can say C = pi * D

Using the value of 22/7 for pi and the value of the circumference in the question, we have;

135 = 22/7 * D

D = (7 * 135)/22

D = 42.95 feet

Naya [18.7K]3 years ago
4 0

Answer: 43feet

Step-by-step explanation:

Perimeter= 135 feet

Since perimeter= 2πr

135 = 2πr

Recall that π = 3.14

135 = 2 × 3.14 × r

135 = 6.28 × r

135 = 6.28r

r = 135/6.28

r = 21.5

d = 2r

d = 2 × 21.5

d = 43 feet

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anyanavicka [17]
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When you do the calculation; \frac{422}{59}=7.15 You get 7.15 shelves. Clearly you cannot have .15 of a shelf so the logician in me wants to say you need 8 shelves! 

But if the assignment is aimed estimation skills, (Which is what I assume is being implied by the title of the assignment), then the easier calculation of \frac{420}{60}=7 is probably what the teacher was hoping for.

You might have been accidentally been calculating \frac{59}{422} =.139. Remember division is NOT communitive! i.e.1\div2\neq2\div1.

From the image;
The first step was to see that 59 can not go into 4..resulting in the zero above the 4, multiplying 0 by 59 and subtracting 0 from 4. 

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The third step begins by bringing down the 2, seeing that 59 can go into 422 7 times (I tested this on the right by a short multiplication problem)..resulting in the 7 above the 2, multiplying 7 by 59 and subtracting 413 from 42.

This process continues....

8 0
3 years ago
Read 2 more answers
I need help! I would appreciate if you show me the work! Thank you !
iVinArrow [24]

Answer:

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Step-by-step explanation:

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frozen [14]

Answer:

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Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

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I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

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I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

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3 years ago
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3 years ago
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Answer:

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