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blsea [12.9K]
2 years ago
8

2a – 7 + 4b + 7a – b + 4

Mathematics
1 answer:
Contact [7]2 years ago
5 0

Answer:

(2a+7a)+(−7+4)+(4b−b)

9a−3+3b

Brainlist Pls!

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You made two deposits to your bank accounts this month. One deposit was $17.92, and the second deposit was $15.33. Your balance
WITCHER [35]



$72.31  is the total amount AFTER ADDING TWO DEPOSITS

So, if we want to know the amount before deposits, we just need to take the total of previous two deposits

The expressions that show your balance would be

$72.31 – $17.92 – $15.33;    $39.06
6 0
3 years ago
What is the equation that passes through the points (-2,-4) & (8,1) ??? Please help thanks.
Marizza181 [45]
To solve a Linear equation we need to find the slope:

-4-1 / -2-8 =1/2

now that we have the slope we can find our x and y
y-1=1/2(x-8)
y=x/2-3
5 0
2 years ago
What is the square of one half?
Vlad1618 [11]

Answer:

One-half squared is one-fourth.

Step-by-step explanation:

When you divide fractions, you multiply the first term by the reciprocal of the second term. In this example, instead of multiplying 1/2 by 1/4, you now multiply 1/2 by 4. Therefore, one half is equal to 2 fourths.

3 0
2 years ago
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Find the angle of depression from the top of a lighthouse, 260 feet above water to a ship that's 270 feet offshore?
expeople1 [14]

Answer: OPTION C.

Step-by-step explanation:

Observe the triangle ABC attached.

Notice that the angle of depression is represented with \alpha.

Knowing that the top of a lighthouse is 260 feet above water and the ship is 270 feet offshore, you can find the value of  \alpha by using arctangent:

\alpha= arctan(\frac{opposite}{adjacent})

In this case you can identify that:

opposite=260\\adjacent=270

Therefore, substuting values into  \alpha= arctan(\frac{opposite}{adjacent}), you get that the angle of depression is:

 \alpha= arctan(\frac{260}{270})\\\\\alpha=43.92\°

4 0
3 years ago
Chris shoots an arrow up into the air. The height (in feet) of the arrow is given by the function h(t) = - 16t2 + 64t + 112 wher
iris [78.8K]

Answer:

After 2 seconds

Step-by-step explanation:

First step is find an equation of velocity:

h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.

v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.

Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.

0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ \frac{32t}{32}=\frac{64}{32}

t=2. That means after 2 sec. the arrow reach the maximum height

6 0
3 years ago
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