A= 1/360 pi r ^2
A= 252/360 pi 10^2
A= 70pi
Part A:
Significant level:
<span>α = 0.05
Null and alternative hypothesis:
</span><span>h0 : μ = 3 vs h1: μ ≠ 3
Test statistics:
P-value:
P(-0.9467) = 0.1719
Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438
Conclusion:
Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.
Part B:
The power of the test is given by:
Therefore, the power of the test if </span><span>μ = 3.25 is 0.8105.
Part C:
</span>The <span>sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:
Therefore, the </span>s<span>ample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.</span>
Answer:
40/3
Step-by-step explanation:
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Answer: 700 yards of fencing (assumed).
Step-by-step explanation:
To be able to calculate the number of yards that Farmer Johnson needs, you will have to know the dimensions of the field.
I will therefore assume certain figures and you can use it as a reference.
Assume that the field is a rectangular field that measures 200 yards in length and 150 yards in breath.
This means that the amount of yards needed will be the perimeter of the yard:
Perimeter = (Length * 2) + (Width * 2)
= (200 * 2) + ( 150 * 2)
= 400 + 300
= 700 yards of fencing.
I would say 1 would be the least possible remainder...
11/5 = 2 remainder 1
21/5 = 4 remainder 1
31/5 = 3 remainder 1
and since ur dealing with positive integers (whole numbers), 1 is gonna be the smallest