[see picture link]Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Picture: https://us-static.z-dn.net/files/d30/9033549987fa60cf57fe05f71424f322.gif
Answer:
x <7
Step-by-step explanation:
3x – 4 < 17
Add 4 to each side
3x – 4+4 < 17+4
3x < 21
Divide each side by 3
3x/3 < 21/3
x <7
Answer: 11/10 is your answer
Step-by-step explanation: Hoped this helped
Answer: 9
Step-by-step explanation:
if:
y=5.4........................x=3
y=?.............................x=5
y=(5.4*5)/3=9
The complete question is
"A 4 inch by 6 inch picture is placed in a frame that creates a uniform border of x inches around the picture. The area of the entire frame (including where the picture is placed) is equal to 55.25 square inches.
What will be the width and length of the frame?"
The width of the frame is 4+2x, and the length of the frame is 6+2x.
<h3>What is the area of the rectangle?</h3>
The area of the rectangle is the product of the length and width of a given rectangle.
The area of the rectangle = length × Width
We know that the picture is 4 inches wide and 6 inches long.
Since there is a uniform border of x inches around the picture, so we must add 2x inches to each dimension.
The area will be = (4+2x)(6+2x) = 55.25
Therefore, the width of the frame is 4+2x, and the length of the frame is 6+2x.
Learn more about the area;
brainly.com/question/1658516
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