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g100num [7]
3 years ago
13

If a case holds 12 items how many cases would you need to transport 159 items

Mathematics
2 answers:
guajiro [1.7K]3 years ago
5 0
13.25 cases but round that up to 14 cases to transport 159 items. 159÷12=13.25
Ahat [919]3 years ago
3 0

14 cases i really hope this helps


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Write the expression that shows 3 time the sixth power of 10
77julia77 [94]
3 x 10^6

Shouldn't be too hard for ya ;)
8 0
3 years ago
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
Times
liubo4ka [24]

Answer:

40 times

Step-by-step explanation:

8 times per 2 months

10 months / 2 months = 5 months

5 months x 8 times =  40 times

8 0
3 years ago
Can somebody plz answer questions 13-18 correctly thank you!
erik [133]

Answer:

13. 20%

14.7%

15. 3.5%

16.45%

17. 84%

18. 68.5%

3 0
3 years ago
Give your answer as a whole number or as a mixed number in its simplest form.​
katrin2010 [14]

Answer:

5 3/7

Step-by-step explanation:

On this one all you basically have to do is 4+1 since they are both whole numbers, then attatch the fraction onto that.

4+1=5

5 3/7

6 0
2 years ago
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