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Brut [27]
3 years ago
6

Find the radius of a circle with a circumference of 30 units. Round your answer to the nearest tenth (1 decimal place).

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

The radius would be 4.8

Step-by-step explanation:

The circumerfence of a circle can be found use the equation C=2\pir. So since we are given the circumerce we need to rearrange the eqaution to it looks like \frac{30}{2\pi }=r. when we do this out we find that the radius equals 4.8.

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The hypotenuse of a right triangle is four times the length of one of the legs. The length of the other leg is 1500⎯⎯⎯⎯⎯⎯⎯⎯√ fee
Mrac [35]

Answer:

Step-by-step explanation:

So this is just playing with the pythagorean theorem

a^2 + b^2 = c^2 with a and b as legs and c as the hypotenuse.

Let's say a is equal to 1500 so then c is 4 times b

1500^2 + b^2 = (4b)^2  Now we just treat this like a normal algebraic expression

2,250,000 = 16b^2 - b^2

2,250,000 = 15b^2

150,000 = b^2

sqrt(150,000) = b

100sqrt(15) = b

You can check this now.

1500^2 + sqrt(150,000)^2 = c^2

sqrt(2,250,000 + 150,000) = c

sqrt(2,400,000) = c

400sqrt(15) = c Which fits the requirement of c = 4b

7 0
3 years ago
Which problem can we solve with 1/2 / 7?
strojnjashka [21]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
Given g(x) = -x + 3, solve for x when g(x) = -1.
cluponka [151]

Answer:

4

Step-by-step explanation:

It's ok! This is simple. Simply plug in your given values. Since g(x) = -1, plug that into the equation.

g(x) = -x + 3

g(-1) = -(-1) + 3

=1+3

=4

7 0
3 years ago
Which of the following is not a measure of central tendency?
Effectus [21]

Answer:d). standard deviation

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the equation of a line which includes points (-5, 5) and (2, 5)?
sveta [45]
<h2>Hello!</h2>

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

y=5

<h2>Why?</h2>

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)

So, using the points (-5,5) and (2,5), we have:

y-5=\frac{5-5}{2-(-5)}*(x-(-5))

y-5=\frac{0}{2+5}*(x-(-5))

y-5=0*(x+5)

y-5=0

y=5

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

y=5

Have a nice day!

Note: I have attached a picture for better understanding.

8 0
3 years ago
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