Answer:
Perimeter = 21.58 units
Step-by-step explanation:
Perimeter of a polygon = Sum of measures of all sides of the polygon
Perimeter of the quadrilateral LEAP = PL + AE + EL + LP
= 4.47 + 4.47 + 6.32 + 6.32
= 21.58 units
[If the distances between two point are not given, use the formula to calculate the distance between two points
and 
Distance =
]
Answer:
B. 6.000000 g
Step-by-step explanation:
The reason why its B is due to it having more 'sigs' than 'figs'
Hope this helped <3
Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane
, then r will have the next parametric equations:

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

Substitute the value of
in the parametric equations:

Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane

You find a common denominator (the bottom one) and then add the numerator (the top) but you don't add the denominator, you just make it the same
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.