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Musya8 [376]
2 years ago
9

Given P(A)=0.34P(A)=0.34, P(B)=0.45P(B)=0.45 and P(A\text{ or }B)=0.517P(A or B)=0.517, find the value of P(A\text{ and }B)P(A a

nd B), rounding to the nearest thousandth, if necessary.
Mathematics
1 answer:
maria [59]2 years ago
8 0
Easy this answer is going to be 0.517 you can read and round
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Uh i need help with those 3, will give brainliest, thanks!
rusak2 [61]

Answer:

26 = G. 27 = A. 28 = J

Step-by-step explanation:

26} A Nickle = 5 cents. A Dime = 10 Cents.

Way #1: 5+5+5+5+5+5 = 30

Way #2: 10 + 10 + 10 = 30

Way #3: 10 + 5 + 5 + 5 + 5 = 30

Way #4: 10+ 10+ 5 + 5 = 30

27} Pennies = 1 Cent. Nickels = 5 Cents. Dimes = 10 cents.

Way #1: 1+1+1+1+1+5+ 10 = 20

28} Pennies = 1 Cent. Nickels = 5 Cents. Dimes = 10 Cents.

Way #1: 10+5+1+1 = 17

Way #2: 5+5+5+11 = 17

Way #3: 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1 = 17

Way #4: 1+1+1+1+1+1+1+10 = 17

Way #5: 5+1+1+1+1+1+1+1+1+1+1+1+1 = 17

5 0
2 years ago
Help!!!!! No weird answers pls
Papessa [141]

open the parenthes. and then after that you'll get 27+12x-15. if you simplify that then you'll get 12x+12

7 0
3 years ago
Read 2 more answers
PLEASE LOOK AT THIS multiple choice, thanks.
Y_Kistochka [10]

Answer:

The answer should be y= -2x + 8

Step-by-step explanation:

4 0
3 years ago
According to the Department of Transportation, 27% of domestic flights were delayed in the last year at JFK airport. Five flight
Mars2501 [29]

Answer:

The probability that all the five flights are delayed is 0.2073.

Step-by-step explanation:

Let <em>X</em> = number of domestic flights delayed at JFK airport.

The probability of a domestic flight being delayed at the JFK airport is, P (X) = <em>p</em> = 0.27.

A random sample of <em>n</em> = 5 flights are selected at JFK airport.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={5\choose x}0.27^{x}(1-0.27)^{5-x};\ x=0,1,2...

Compute the probability that all the five flights are delayed as follows:

P(X=5)={5\choose 5}0.27^{5}(1-0.27)^{5-5}=1\times 1\times 0.207307=0.2073

Thus, the probability that all the five flights are delayed is 0.2073.

4 0
3 years ago
Here are the population figures of five different cities. 371,265 635,155 226,710 468,920 724,435 What is the difference between
Aleksandr-060686 [28]

Answer:

497,725

just subtract smallest from largest to get the difference

724,435 - 226,710

4 0
2 years ago
Read 2 more answers
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