Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Answer:
A I think because no matter where u start they're not symmetrical
20° is the answer if you look on the other side
Answer:
Ryo ordered 
of the amount of eggs his restaurant needed
Step-by-step explanation:
Let's call z the number of eggs the restaurant needs
Ryo ordered 240% of the eggs he needed. Then Ryo ordered:
z.
This fraction can be simplified by dividing by 10 in the numerator and denominator.
Then it is:
It can be further simplified by dividing by 2 in the numerator and denominator:
z
Ryo ordered of the amount of eggs his restaurant needed
1/2-1/4
(1/2x2)-1/4
2/4-1/4
2-1
1
1/4
