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nexus9112 [7]
2 years ago
14

Together, two apples have 175 gram of fat. How many apples have a total of 4 grams of fat?

Mathematics
1 answer:
inysia [295]2 years ago
4 0

I'm pretty sure if the answer accepts decimals, if two apples = 175 grams, then one apple equals 87.5 grams, and if we want an apple that equals four grams, it would be less than one apple so we would divide the grams of one apple till it equals 4, therefore 87.5/4 = 21.875

P.S. im not entirely sure this is right im just trying to help :)

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2(4 - 2r) = -2(r + 5)
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2(4 - 2r) = -2(r + 5)

First, divide both sides by -2. / Your problem should look like: -4 + 2r = r + 5
Second, regroup your terms. / Your problem should look like: 2r - 4 = r + 5
Third, add 4 to both sides. / Your problem should look like: 2r = r + 5  + 4
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:2r = r + 9
Fifth, subtract r from both sides. / Your problem should look like: 2r - r = 9
Sixth, subtract 2r - r to get r. / Your problem should look like: r = 9

Answer: r = 9

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A cable is 84 meters long, it is cut into two pieces so that one piece is 18 meters longer than the other. Find the length of ea
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Long Piece: x + 18

Short Piece: x

(x) + (x + 18) = 84

2x + 18 = 84

2x = 66

x = 33

Long Piece: x + 18  = (33) + 18   = 51

Answer: 33 meters and 51 meters

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3 years ago
Lily's car has a fuel efficiency of 8 liters per 100 kilometers. What is the fuel efficiency of Lily's car in kilometers per lit
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Answer:

The fuel efficiency of Lily's car in kilometers per liter is 12.5 km/litre.

Step-by-step explanation:

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Suppose parts (a) through (d) below provide results for a study on the role of calcium in reducing the symptoms of PMS. For each
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Answer:

Step-by-step explanation:

Hello!

To test if calcium reduces the symptoms of PMS two independent groups of individuals are compared, the first group, control, is treated with the placebo, and the second group is treated with calcium.

The parameter to be estimated is the difference between the mean symptom scores of the placebo and calcium groups, symbolically: μ₁ - μ₂

There is no information about the distribution of both populations X₁~? and X₂~? but since both samples are big enough, n₁= 228 and n₂= 212, you can apply the central limit theorem and approximate the sampling distribution to normal X[bar]₁≈N(μ₁;δ₁²/n) and X[bar]₂≈N(μ₂;δ₂²/n)

The formula for the CI is:

[(X[bar]₁-X[bar]₂) ± Z_{1-\alpha /2} * \sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} }]

95% confidence level Z_{1-\alpha /2}= Z_{0.975}= 1.96

(a) mood swings: placebo = 0.70 ± 0.78; calcium = 0.50 ± 0.53

X₁: Mood swings score of a participant of the placebo group.

X₂: Mood swings score of a participant of the calcium group.

[(0.70-0.50) ± 1.96 * \sqrt{\frac{0.78^2}{228} +\frac{0.53^2}{212} }]

[0.076; 0.324]

(b) crying spells: placebo = 0.39 + 0.57; calcium = 0.21 + 0.40

X₁: Crying spells score of a participant of the placebo group.

X₂: Crying spells score of a participant of the calcium group.

[(0.39-0.21) ± 1.96 * \sqrt{\frac{0.57^2}{228} +\frac{0.40^2}{212} }]

[0.088; 0.272]

(c) aches and pains: placebo = 0.45 + 0.60; calcium = 0.37 + 0.45

X₁: Aches and pains score of a participant of the placebo group.

X₂: Aches and pains score of a participant of the calcium group.

[(0.45-0.37) ± 1.96 * \sqrt{\frac{0.60^2}{228} +\frac{0.45^2}{212} }]

[-0.019; 0.179]

(d) craving sweets or salts: placebo = 0.60 + 0.75; calcium = 0.44 + 0.61

X₁: Craving for sweets or salts score of a participant of the placebo group.

X₂: Craving for sweets or salts score of a participant of the calcium group.

[(0.60-0.44) ± 1.96 * \sqrt{\frac{0.75^2}{228} +\frac{0.61^2}{212} }]

[0.032; 0.287]

I hope this helps!

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