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2 years ago

I need help ! please asap!!!!

Mathematics

1 answer:

lutik1710 [3]2 years ago

5 0

Answer:

C & F

Step-by-step explanation:

29 - 13 is 16 and 46 - 21 is 25. Everything else is wrong because the differences are not the correct answers except for C and F. Sorry if this sounds kinda confusing

This is probably wrong so...

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Right now I have a selected but I’m not sure if that’s right please help

LenaWriter [7]

The answer is C or 12 because it has to equal to 180 so 5(12) + 5 = 65 and 65 + 115 = 180

4 0

2 years ago

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What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfractio

ziro4ka [17]

The simplified form of the given equation is $=\frac{6}{5x^{10}}$

We have given that,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

Apparently, you want to simplify the given equation,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

The applicable rules of exponents are,

<h3>What is the exponent rule?</h3>

(a^b)(a^c) = a^(b+c)

1/a^b = a^(-b)

(a^b)^c = a^(bc)

So the expression simplifies as

$=\sqrt{\frac{72x^{16}}{50x^{36} }}\\\\=\frac{6}{5x^{10}}$

Therefore the simplified form of the given equation is $=\frac{6}{5x^{10}}$

To learn more about exponential form visit:

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2 years ago

Start at 5 3/4 subtract 3/8

Lady_Fox [76]

You change the fraction so that they will have the same denominator. This makes it 5 6/8 minus 3/8. The answer is 5 3/8

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2 years ago

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Use synthetic division to find the result when x^4-2x^2-4x-48 is divided by x-3

just olya [345]

Answer: it’s x^3+3x^2+7x+17+3/x-3

Sorry ab the handwriting lol

Step-by-step explanation:

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2 years ago

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

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3 years ago