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Nimfa-mama [501]
3 years ago
15

Cho hình chóp SABCD. Lấy I thuộc SA, J thuộc SB sao cho IJ không song song với AB. Lấy điểm K trong miền tứ giác ABCD. Tìm đường

cao tuyến của I, J, K với các mặt sau đây: ABCD, SBC, SAD, SCD
Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

Step-by-step explanation:

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5 more than the quotient of a number and 8 is 42
Zepler [3.9K]

Answer:

<u>The number is 296.</u>

Step-by-step explanation:

Let's call "x" to the number we are looking for.

Now, the problem states that "5 more than the quotient of a number and 8 is 42". This means that this number is being divided by 8, it's also being additioned 5 and the final result is 42. Therefore, the expression of this operations on this number is the following:

\frac{x}{8}+5=42. Let's solve the equation to find x.

1. Write the expression.

\frac{x}{8}+5=42

2. Substract 5 from both sides and simplify.

\frac{x}{8}+5-5=42-5\\\\\frac{x}{8}=37\\\\

3. Multiply 8 on both sides and simplify.

8*\frac{x}{8}=37*8\\\\x=296

<u>We have found our number, it's 296!</u>

3 0
2 years ago
Read 2 more answers
How exactly do you do this because my teacher didn't teach me how
mylen [45]
The area is found by base x height

To find the missing height in the first one you divide 147 by 15 3/4 and get 9 1/3. 
To find the missing base in the second one you divide 140 5/8 by 11 1/4 and get 12 1/2.
To find the missing height in the third one you divide 151 3/16 by 10 1/4 and get 14 3/4. 

Make me brainliest ! :)

6 0
3 years ago
17 &lt; 2x + 7 &lt;29*<br> Your Inswer
borishaifa [10]

Answer:

5<x<11

Step-by-step explanation:

4 0
3 years ago
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Kiera dance class starts at 4:30 pm and ends at 6:15. hiw long is her dance class
AleksAgata [21]
Her dance class is 1 hour and 45 minutes long 

Hope this helps!
5 0
3 years ago
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Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2
mihalych1998 [28]

Answer:

y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

y''+6y'+10y=0

<u>Use Auxiliary Equation</u>

<u />m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i

<u>General Solution</u>

<u />y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Note that the DE has two distinct complex solutions p\pm qi where A and B are arbitrary constants.

4 0
2 years ago
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