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suter [353]
3 years ago
8

Please help me I'm stuck on this problem.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

D: MN/LM = RS/QR

Step-by-step explanation:

ΔSQR ~ ΔNLM

MN/LM = RS/QR

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Can someone pls tell me how to solve this
miv72 [106K]
Since we find the cube root of 216, we get 6, which is the answer
8 0
3 years ago
Read 2 more answers
Write an expression for the area of the shaded region in its simplest form. Show all of your steps.
netineya [11]
The area of the shaded region is going to be the area of the rectangle minus the area of the square.

Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle

area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1

now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.

2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
6 0
3 years ago
The base of the pyramid is a right triangle<br><br><br><br> The volume is ____ cubic cm.
kompoz [17]

Answer:

37 cubic cm should be the answer sorry if I am wrong

3 0
3 years ago
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
In what time the compound amount of Rs 60000 at 10% rate is rs 79860?​
Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

    = 3/2 x 2 = 3 half years

R= ?  

Applying the formula A= P (1+r/100)^T

           79860  = 60000 (1+ r/100)^3

                  79860/60000 = (1+r/100)^3

                  1331/1000 = (1+r/100)^3

root(3)(1331/1000) = (1+r/100)

                     11/10 = 1+r/100

                     11/10 -1 = r/100

                      1/10 = r/100

                       r= 10 %

Step-by-step explanation:

8 0
3 years ago
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