Since we find the cube root of 216, we get 6, which is the answer
The area of the shaded region is going to be the area of the rectangle minus the area of the square.
Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle
area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1
now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.
2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
Answer:
37 cubic cm should be the answer sorry if I am wrong
The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.
<h3>What is the significance of "Area under the curve"?</h3>
This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.
<h3>What is the justification for the above answer?</h3>
Area = 
= 
= e¹-(1/2-0); or
Area = e -1.5 Squared Unit
The related Graph is attached accordingly.
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Answer:
P= Rs 60000
A= Rs 79860
T=1 & 1/2 year = 3/2 years
= 3/2 x 2 = 3 half years
R= ?
Applying the formula A= P (1+r/100)^T
79860 = 60000 (1+ r/100)^3
79860/60000 = (1+r/100)^3
1331/1000 = (1+r/100)^3
root(3)(1331/1000) = (1+r/100)
11/10 = 1+r/100
11/10 -1 = r/100
1/10 = r/100
r= 10 %
Step-by-step explanation: