4x - 3y = -11
-7x - 8y = 6
We need to cancel out one of the variables so let's multiply the first equation by 8 and the second by 3 and aim to cancel y.
32x - 24y = -88
-21x - 24y = 18
Now we subtract,
53x = -106
x = -2
3y = 4x + 11 = 4(-2) + 11 = 3
y = 1
Answer: (x,y)=(-2,1)
Check:
4(-2) -3(1) = -8 - 3 = -11, good
-7(-2) - 8(1) = 14 - 8 = 6, good
V≈2714.34ft³I hope this answer your question.
I’m pretty sure it’s b because they are camouflaged
Without the graph it is impossible the find the value of K
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table