Question

given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line. 3/2 2/3 -3/2

Answer 1

2x-3y-5=0
2x-5=3y
3y=2x-5
y=$\frac{2}{3} x- \frac{5}{3}$
Gradient of line 1 = $\frac{2}{3}$
Gradient of line 2;
$m_{1} * m_{2} =-1$
$m_{2} * \frac{2}{3} =-1$
$m_{2} =- \frac{3}{2}$