Answer:
YX and WX
Step-by-step explanation:
In an isoceles triangle, the sides WX and YX are equal which also means you can assume angle W and angle Y are also equal.
I believe B or C but that’s a straight guess. i would say B just because if you live like outside of town then ur screwed
Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as: 
Area of a rectangle is calculated as: 
Area of a right trapezoid is:
, where:
a is short base
b is long base
h is height
1) Expressing areas in terms of x:
Area of triangle S1:


Area of rectangle S2:


Area of trapezoid S3:



2) a) 


Which is the same as S = (2x-3)(5x-9)
b) For the areas to be the same:




Using Bhaskara to solve the second degree equation:

= 1.8
= 1.5
For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.
c) <u>Expand</u> <u>a</u> <u>polynomial</u> (or equation) is to multiply all the terms, remiving the parenthesis. <u>Reduce</u> <u>a</u> <u>polynomial</u> (or equation) is to combine terms alike,e.g.:

(expand)
(reduce)
d) For area of AFCG to be bigger than area of ADEB by 27:



Solving:


2.82
= 0.48
According to the enunciation, x cannot be less than 1.5, then, the value of x so that area AFGC exceeds the area ADEB by 27 is 2.82
5/6 divide by 4 equals 5/24. So each plot would be 5/24 km squared. Multiply that by 3 and it would be 15/24. So the answer would be 15/24 km squared if im correct.
See the attached figure which represents the explanation of the problem.
Let <span>the height of the building = h
</span>
∵ ∠1 congruent to ∠2
∴ ∠1 = ∠2
∴ tan (∠1) = tan (∠2) ⇒⇒⇒ tan of the angle = (opposite/adjacent)
∴

∴ 12 h = 5 * 264 = 1,320
∴ h = 1,320/12 = 110 feet
∴ T<span>
he height of the building = 110 feet</span>