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zloy xaker [14]
3 years ago
9

The populations of Cities A and B are 1.6 x 10^5 and 1,070,000​, respectively. The population of City C is twice the population

of City B. The population of City C is how many times the population of City​ A?
Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

Answer:

13

Step-by-step explanation:

First find the population of city c 1,070,000 times 2 = 2140000

Round 2140000 to the nearest hundred thousands = 2,100,000

Third find how many places the decimal moves which is 6 places

Fourth scientific notation of 2,100,00 is 2.1 times 10^6

Fifth divided city c by the population of city a

2.1x 10^6 divided by 1.6 x 10^5

2.1 / 1.6 rounded is 1.3

10^6 divided by 10 ^ 5 is 10

Therefore 2.1 x 10^6 divided by 1.6 divided by 10^5 equals 1.3 times 10 = 13

The population of city c is about 13 times the population of city a

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Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = \frac{3}{4},

q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28

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