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Alenkinab [10]
3 years ago
9

WILL MARK BRAINLEST IF CORRECT HELP ME OUT

Mathematics
1 answer:
sveta [45]3 years ago
6 0

Answer:

x = 12

Step-by-step explanation:

Equation:    0.52(x) + 0.72(4) = 0.57(x + 4)

0.52(x) + 0.72(4) = 0.57(x + 4)             \longmapsto         Multiply

0.52x + 2.88 = 0.57x + 2.28               \longmapsto         Subtract 0.52x from both sides

2.88 = 0.05x + 2.28                            \longmapsto         Subtract 2.28 from both sides

0.6 = 0.05x                                          \longmapsto        Divide all sides by 0.05

 

x = 12

-Chetan K

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(3xy/3x^2-12)*(x^2+3x+2/xy+y)
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Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

<u>Step-by-step explanation:</u>

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y)  or ,

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

Let's simplify this

⇒ (\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})

Factorizing the terms we get:

⇒ (\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})              { a^2-b^2=(a+b)(a-b)      }

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})

Cancelling similar terms we get:

⇒ \frac{x}{x-2}

Therefore , Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

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