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3 years ago

A graph of f(x) = 6x2 - 11x + 3 is shown on the grid.

Mathematics

2 answers:

Setler79 [48]3 years ago

7 0

Answer:b

Step-by-step explanation:

spin [16.1K]3 years ago

7 0

Answer: 2 and 9

Step-by-step explanation: just trying to help people out!

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Factorisation with this question, please help

charle [14.2K]

3( x - y )^2 - 2( x - y ) =

( x - y ) ( 3( x - y) - 2 ) =

( x - y )( 3x - 3y - 2 )

8 0

3 years ago

Dawn has 5/6 of a yard of lace. She uses 4/5 of it for a dress and the rest of it for a jewel box. How much does she use for the

never [62]

5/6-4/5=1/30
She uses 1/30 yard of lace for the jewel box.

3 0

4 years ago

Read 2 more answers

Solve for x: z=m-x *

astraxan [27]

Answer:

x = m - z

Step-by-step explanation:

z = m - x

Add x to both sides.

x + z = m

Subtract z from both sides.

x = m - z

8 0

3 years ago

Wha is the value of x if the quadrilateral is a kite

Lorico [155]

x+2=13

x=11

Hope this helps :)

5 0

4 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

7 0

3 years ago