Answer:
you graph it
Step-by-step explanation:
put it in yo cal
Answer: 34.2
For everyone 1 kilometer=.621371 so if you times that by 55 you get 34.1754 which rounds to 34.2
Answer:
14 gallons....$42
Step-by-step explanation:
The car requires one gallon every 32 miles...
The car requires c gallons for 448 miles
c = 448 × 1 / 32
= 14 gallons..
One gallon = $3
Fourteen gallons = ??
14 × 3 / 1 = $42
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³