Answer:
c. 59.3 ft²
Step-by-step explanation:
½× [(3.14×5²) + (10×4)]
= ½ × (78.5+40)
= ½× 118.5
= 59.3
Given that <span>Line WX is congruent to Line XY and Line XZ bisects Angle WXY.
We prove that triangle WXZ is congruent to triangle YXZ as follows:
![\begin{tabular} {|c|c|} Statement&Reason\\[1ex] \overline{WX}\cong\overline{XY},\ \overline{XZ}\ bisects\ \angle WXY&Given\\ \angle WXY\cong\angle YXZ & Deifinition of an angle bisector\\ \overline{XZ}\cong\overline{ZX}&Refrexive Property of \cong\\ \triangle WXZ\cong\triangle YXZ&SAS \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AStatement%26Reason%5C%5C%5B1ex%5D%0A%5Coverline%7BWX%7D%5Ccong%5Coverline%7BXY%7D%2C%5C%20%5Coverline%7BXZ%7D%5C%20bisects%5C%20%5Cangle%20WXY%26Given%5C%5C%0A%5Cangle%20WXY%5Ccong%5Cangle%20YXZ%20%26%20Deifinition%20of%20an%20angle%20bisector%5C%5C%0A%5Coverline%7BXZ%7D%5Ccong%5Coverline%7BZX%7D%26Refrexive%20Property%20of%20%5Ccong%5C%5C%0A%5Ctriangle%20WXZ%5Ccong%5Ctriangle%20YXZ%26SAS%0A%5Cend%7Btabular%7D)
</span>
Corresponding angles for parallel lines r and s cut by transversal q. Corresponding angles are congruent angles.
1 and 9
2 and 10
3 and 11
4 and 12
Corresponding angles for parallel lines p and q cut by transversal s. Corresponding angles are congruent angles.
11 and 15
9 and 13
12 and 16
10 and 14
Corresponding angles for parallel lines p and q cut by transversal r. Corresponding angles are congruent angles.
1 and 5
3 and 7
2 and 6
4 and 8
Linear pair theorem. These 2 angles are equal to 180°
∠1 + ∠2 = 180
∠3 + ∠4 = 180
∠9 + ∠10 = 180
∠11 + ∠12 = 180
∠5 + ∠6 = 180
∠7 + ∠8 = 180
∠13 + ∠14 = 180
∠15 + ∠16 = 180
∠1 + ∠3 = 180
∠2 + ∠4 = 180
∠9 + ∠11 =180
∠10 + ∠12 = 180
∠5 + ∠7 = 180
∠6 + ∠8 = 180
∠13 + ∠15 = 180
∠14 + ∠16 = 180
Vertical angles theorem. Vertical angles are congruent.
1 and 4
2 and 3
9 and 12
10 and 11
5 and 8
6 and 7
13 and 16
14 and 15
Answer:
The answer is B) 152
Step-by-step explanation:
