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adell [148]
3 years ago
11

Janelle has a babysitting job for the sunumer. She works from 7 AM to 2 P.M. with a 30-minute, unpaid break in the middle of the

day. She is paid $4.50 per hour. How much money does Janelle make in 5 days?​
Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer: $146.25

Step-by-step explanation:

To solve the question, we need to first calculate the number of hours between 7 AM to 2 P.M which is 7 hours but we are told that there is a 30 minutes break. Therefore, he works for 6 hours 30 minutes which is 6 1/2 hours.

She's paid $4.50 pee hour, therefore the amount paid per day will be:

= 6 1/2 × $4.50

= 6.50 × $4.50

= $29.25

The amount that she'll make in 5 days will be:

= $29.25 × 5

= $146.25

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You need to fertilize 0.35 acres of land. the fertilizer is spread by the square yard .how many square yards of land do you have
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Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

you have to divide the total money raised by the amount sold

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each ticket was $35

and to make sure its correct you can always multiply the amount of 1 ticket to the amount sold

475*35=16,625

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3 years ago
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