What is 0.02% written as a decimal

The following table shows a portion of a five-year amortization schedule. A 5-year amortization schedule. Loan amount or princip

kogti [31]

The percentage of the payments made were due to interest is 32.6 %. Then the correct option is B.

<h3>What is the percentage?</h3>

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

The following table shows a portion of a five-year amortization schedule.

A 5-year amortization schedule.

Loan amount or principal: 10,900 dollars.

The interest rate on loan: 10. 95 percent.

The table will be

Month Payment Principal Interest Balance

15 236.72 155.87 80.85 8704.27

16 236.72 157.29 79.43 8546.98

17 236.72 158.73 77.99 8388.25

18 236.72 160.18 76.54 8228.07

19 236.72 161.64 75.08 80.66.43

20 236.72 163.11 73.61 7903.32

Total payment = 6 × 236.72 = $ 1420.32

Total interest = 80.85 + 79.43 + 77.99 + 76.56 + 75.08 + 73.61

Total interest = $ 463.38

Then the percentage will be

$\rm Percentage = \dfrac{463.38}{1420.32}*100\\\\Percentage = 32.625 \approx 32.6\ \%$

More about the percentage link is given below.

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What is the equation of the line that passes through the point (-3,2) and has a slope of -3

Crank

Answer:

y = -3x-7

Step-by-step explanation:

y = mx + b

y = -3x + b => 2 = -3(-3) + b => b = -7

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Vesnalui [34]

I don’t listen to song. It’s HARAM. I’m Muslim. :))

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discrete random variable X has the following probability distribution: x 13 18 20 24 27 P ( x ) 0.22 0.25 0.20 0.17 0.16 Compute

tatuchka [14]

Answer:

(a) P(X = 18) = 0.25

(b) P(X > 18) = 0.53

(c) P(X ≤ 18) = 0.47

(d) Mean = 19.76

(e) Variance = 22.2824

(f) Standard deviation = 4.7204

Step-by-step explanation:

We are given that discrete random variable X has the following probability distribution:

X P (x) X * P(x) $X^{2}$ $X^{2}$ * P(x)

13 0.22 2.86 169 37.18

18 0.25 4.5 324 81

20 0.20 4 400 80

24 0.17 4.08 576 97.92

27 0.16 4.32 729 116.64

(a) P ( X = 18) = P(x) corresponding to X = 18 i.e. 0.25

Therefore, P(X = 18) = 0.25

(b) P(X > 18) = 1 - P(X = 18) - P(X = 13) = 1 - 0.25 - 0.22 = 0.53

(c) P(X <= 18) = P(X = 13) + P(X = 18) = 0.22 + 0.25 = 0.47

(d) Mean of X, $\mu$ = ∑X * P(x) ÷ ∑P(x) = (2.86 + 4.5 + 4 + 4.08 + 4.32) ÷ 1

= 19.76

(e) Variance of X, $\sigma^{2}$ = ∑ $X^{2}$ * P(x) - $(\sum X * P(x))^{2}$

= 412.74 - $19.76^{2}$ = 22.2824

(f) Standard deviation of X, $\sigma$ = $\sqrt{variance}$ = $\sqrt{22.2824}$ = 4.7204 .

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Find the measure of angle x in the figure below:

rjkz [21]

Times thoghs by each other and see what u get

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