is the expression that represents the perimeter of rectangle
<em><u>Solution:</u></em>
Let "x" represent the width of rectangle
Given that length of rectangle is 3 units shorter than one-third of the width x
length of rectangle = one-third of the width x - 3
<em><u>The perimeter of rectangle is given as:</u></em>
<h3>perimeter of rectangle = 2(length + width)</h3>
Substituting the known values we get,
Thus perimeter of rectangle is
Thus option 1 is correct
Answer:
Not always we can use a calculator to determine if a number is rational or irrational.
Step-by-step explanation:
Consider the provided information.
Can you ever use a calculator to determine if a number is rational or irrational.
Irrational
number: A
number is irrational if it cannot
be
expressed by dividing two
integers. The decimal expansion of
Irrational numbers are neither terminate nor
periodic.
The calculators gives the approximate answer, whether the number is irrational or rational.
- If it shows the terminating decimal then number is rational but otherwise, it is not possible to identify whether the number is rational or irrational as you can only see a few digits.
- Calculator shows the terminating decimal while the decimal expansion of an irrational number is not terminating.
So, it would be difficult to identify whether a large number produced by the calculator is irrational or not. As we know that many rational numbers can be incredibly large.
So, we can say that not always we can use calculator to determine if a number is rational or irrational.
Thus, Not always we can use a calculator to determine if a number is rational or irrational.
Answer:
3/6 is smaller than 6/10...
Step-by-step explanation:
brainliest?
Answer:
a) t (α) = 30 * tan α
b) α = 75 ° is not possible because
Step-by-step explanation:
The vertical cliff (y), the observing partner ( 150 ft ) from the point o ( the common point for the cliff and the ground ) between the cliff, and the line of sight from the observer and the climber, shape a right triangle. Hypothenuse is the distance between the partners, the cliff, and distance of the observer to the cliff are the legs.
Then
α is the elevation angle
tan α = y / 150 (1)
y(t) = elevation of the climber
y(t) = speed * time
y(t) = 5 * t
tan α = 5 *t / 150
tan α = t / 30
t (α) = 30 * tan α
b) α = 75 ° is not possible because:
tan α = y / 150 tan 75° = 3.73
Then y = 3.73 * 150 = 559 ft and the cliff is only 500 ft
