Answer:
Given:
n = 15
c = 95% = 0.95
Let us assume:
α = 0.05
Determine the difference in value of each pair.
→See attached for the table←
→See attached for the for the workings←
Result
a) There is sufficient evidence to reject the claim that the two methods provide the same mean value for natural vibration frequency.
b) (-10.9646, -0.0068)
