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Musya8 [376]
3 years ago
11

Use the given information to find the minimum sample size required to estimate an unknown population mean mu. How many students

must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confidence that the sample mean is within $2 of the population mean, and the population standard deviation is known to be $99.
A) 8296
B) 6630
C) 9413
D) 13,302
Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

9413

Step-by-step explanation:

Given that :

Error = $2 ; Standard deviation (σ) =99 ; α = 95% = 0.95

Zα/2 = Z0. 05/2 = 1.96 (Z probability calculator)...

n = sample size

Recall:

n = ((Zα/2 * σ) / Error)^2

Using the formular above, the sample size n can be obtained ;

n = ((1.96 * 99) / 2)^2

n = 97.02^2

n = 9412.8804

n = 9413

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  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

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<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

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<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

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