All categories

3 years ago

If u give me the right answer I’ll give brainlist

Mathematics

2 answers:

Lemur [1.5K]3 years ago

8 0

Answer:50%

Step-by-step explanation:

scoundrel [369]3 years ago

6 0

Answer:

0% is the answer I think so

You might be interested in

A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels,

VLD [36.1K]

He would use 9 bills, and 5 coins. (fours $10, one $5, four $1. three quarters, one dime, and one penny). I calculated it all to make sure the total came out as 49.86

8 0

3 years ago

Read 2 more answers

Please help asap and I will give Brainliest

Natasha_Volkova [10]

Option A. 5/8 is the correct answer.

Step-by-step explanation:

Square root by factorization will be used to solve this question.

Given

$\sqrt{\frac{25}{64}}$

The square root can be applied to numerator and denominator separately

$=\frac{\sqrt{25}}{\sqrt{64}}$

Factorization

$=\frac{\sqrt{5*5}}{\sqrt{2*2*2*2*2*2}}\\=\frac{\sqrt{5^2}}{\sqrt{2^2*2^2*2^2}}\\=\frac{5}{2*2*2}\\=\frac{5}{8}$

Hence,

Option A. 5/8 is the correct answer.

Keywords: Square roots, factorization

Learn more about square root at:

#LearnwithBrainly

3 0

3 years ago

Hi can someone help me with this its due tommorow!!!

bulgar [2K]

Answer:

1/12

Step-by-step explanation:

Is the answer I'm bro

4 0

3 years ago

Read 2 more answers

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

8 0

3 years ago

Helppppp pleaseeeeee!!!!!!!???????

Arada [10]

I believe the answer is $2.12 (rounded to the nearest cent) explanation: divide the price by the pound for each candy then subtract.

4 0

2 years ago