7x - 1 = 4x + 8
3x = 9
x = 9
ABD
7(3) - 1
21 - 1
20
DBC
4x + 8
4(3) + 8
12 + 8
20
3x - 17 + x + 40 + 2x - 5 = 180
6x + 18 = 180
6x = 198
x = 33
3(33) - 17
99 - 17
82
33 + 40
73
2(33) - 5
66 - 5
61
Sent a picture of the solution to the problem (s). Just rotate pic.
Octogon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon
Answer:
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Step-by-step explanation:
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"<span>Solve Z squared 2 = 1" sounds strange. Do you mean "z squared," or do you mean "Z^2?"
Z^2 = 1 can be solved by finding the sqrt of both sides: Z = plus or minus 1.</span>