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coldgirl [10]
2 years ago
8

Alright, so I have a question that says this:

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
5 0
Octogon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8

area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10

8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon

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cluponka [151]

Answer:x2

Step-by-step explanation:

6 0
3 years ago
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What is 5(n- 1/10) = 1/2
Olegator [25]

Answer:

1/5

Step-by-step explanation:

In order to find the answer, we need to isolate the "n."

Get 5 to the other side by dividing both sides by 5

(n-1/10)= 1/2 ÷(5)

Multiply the 2 and the 5 of the equation.

(n-1/10)= 1/10

Next, move the fraction on the left side, to the right.

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2 years ago
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-28/9-(-5 5/9)
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7 0
3 years ago
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Simplify. Can you explain it also?
Doss [256]

Answer:

The answer is

<h2>\frac{3c}{4e}</h2>

Step-by-step explanation:

<h3>\frac{9 {c}^{3}d {e}^{2}  }{12 {c}^{2} d {e}^{3} }</h3>

To solve the fraction reduce the fraction with d

That's we have

<h2>\frac{9 {c}^{3}  {e}^{2} }{12 {c}^{2} {e}^{3}  }</h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2>{c}^{3}  \div  {c}^{2}  =  {c}^{3 - 2}  = c^{1}  = c</h2>

<u>For </u><u>e</u>

<h2>e^{2}  \div  {e}^{3}  = e^{2 - 3}  =  {e}^{ - 1}  =  \frac{1}{e}</h2>

Substituting them into the expression we have

<h2>\frac{9c}{12e}</h2>

Reduce the fraction by 3

We have the final answer as

<h2>\frac{3c}{4e}</h2>

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8 0
3 years ago
Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theore
velikii [3]

Answer:

RS/VU=ST/UT and ∠S≅∠U

Step-by-step explanation:

we know that

The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar

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∠S≅∠U

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side RS must be proportional to side VU  and side ST must be proportional to side UT

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<em>Verify</em>

substitute the given values

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