Alright, so I have a question that says this:
1 answer:
Octogon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon
sides=4
draw lines from the outside angles to the center so they form 8 equal triangle sections
find the area of each triangle and multiply by 8
area of triangle=1/2 base times height
base=4
the height is the distance from the center of one side of the octogon, to the center=5
so area=4 times 1/2 times 5=4 times 5=10
8 triangles so 8 times 10=80
the answer is 80cm^2
the diagram included below shows area for a pentagon
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<h3>Answer: See the attached image below</h3><h3>Solutions are x = -2 and y = 4</h3>
I've arranged the tiles into the correct positions, and wrote in the final result for each x and y.
The basic idea is to divide determinants as the vertical bars indicate (they aren't absolute value bars).
In each denominator is the determinant of the matrix which are the coefficients of the left hand side of each original equation given to you.
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The numerators are a slight variation of this matrix. The x determinant will have you replace the first column with 0 & 22 getting which helps figure out the x solution. The y solution is similar as well, but we replace the y column instead of the x column. So that explains the
After you have the proper determinants set up, you just evaluate each determinant using the formula
and then simplify the results.