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Oksana_A [137]
3 years ago
14

Emma bought 5 peices of candy from a candy disencer. Each peice of candy costs $0.75. How much money did she spend on candy?​

Mathematics
2 answers:
Jlenok [28]3 years ago
4 0

Answer:

$3.75

Step-by-step explanation:

5*0.75 = 3.75

Just multiply the two numbers together.

ASHA 777 [7]3 years ago
3 0

Answer:

$3.75

Since she claimed that she purchased 5 pieces of candy, each of which cost 0.75, one piece of candy costs 0.75. Since each one costs 0.75, you must multiply 0.75x5 which is 3.75.

Hence, she spent $3.75 on candy

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Please help with this question, thank you
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Remark
The key step is just to subtract 5 from both sides. The pointed of the inequality still points away from the variable and towards the number. As long as that remains true, the correct answer can be found.

Solution
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Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

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The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

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iren [92.7K]

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