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enyata [817]
3 years ago
11

I need help with this. Please and thank you! ❤

Mathematics
2 answers:
Flura [38]3 years ago
8 0
5 to the power of 7
Aka 5x5x5x5x5x5x5
Phantasy [73]3 years ago
5 0

Answer

5 to the power of 7

Explanation

Multiply the length by the width. When multiplying numbers with exponents and similar bases, you can just add the exponents. If this doesn't make sense I'll show you.

The length is 5*5*5*5.

The width is 5*5*5.

Multiply this, and you get 5*5*5*5*5*5*5.

This is 5 times itself seven times.

The area of the rectangle is 5 to the power of 7.

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2.3 x (4 + 12) help plzzzzzzzzzzzxzzzzzzzzxzzzzzxxxzzzzzzzz
Cloud [144]
Do the parentheses first so 12 + 4 = 16

2.3 x 16 = 36.8

The Answer is 36.8
Hope I helped! ( Smiles )
5 0
3 years ago
Read 2 more answers
ben is making bread that calls for 5 cups of flour. His measuring cup only holds 1/2 cup. How many times will ben need to fill t
sladkih [1.3K]

Answer:

10!

Step-by-step explanation:

You will need to put 2 half cups to make 1.

So, 10 half cups is equal to 5 cups.

7 0
3 years ago
Read 2 more answers
Solve the following:<br> 2x - 2 = 4x + 6
olchik [2.2K]

Answer:

x = -4

Step-by-step explanation:

<u>Step 1:  Subtract 2x from both sides</u>

2x - 2 - 2x = 4x + 6 - 2x

<em>-2 = 2x + 6</em>

<em />

<u>Step 2:  Subtract 6 from both sides</u>

-2 - 6 = 2x + 6 - 6

<em>-8 = 2x</em>

<em />

<u>Step 3:  Divide both sides by 2</u>

-8 / 2 = 2x / 2

<em>-4 = x</em>

<em />

Answer:  x = -4

5 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
Pls answer these and thats all
cestrela7 [59]

Answer:

1-

2- Im guessing it means for y since i dont see the answer for x there so D

3-A

Step-by-step explanation:

7 0
3 years ago
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