Algebra 2 help please! I thought i got this one right but it’s wrong.

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Answer:

3x-1*2x+4

6xsquare+10x-4

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daser333 [38]3 years ago

5 0

Answer:

area = 6x^2+10x-4 perimeter= 5x+3

Step-by-step explanation:

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Simplify the expression

NeTakaya

First, solve the parenthesis

Remember to follow PEMDAS, and the left-> right rule

12/3 = 4

4 x 2 = 8

8 + 3 = 11

11 - 7 = 4

Square the remaining number

4² = 4 x 4 = 16

16 is your answer

hope this helps

7 0

3 years ago

What two numbers have an absolute value of 16

Harrizon [31]

Both the negative and positive counterparts of a number have the same absolute value, or distance from 0.

The two numbers are 16 and -16.
They both have the same absolute value, 16.

7 0

3 years ago

Read 2 more answers

The equation (x-3)^2+(y+7)^2=64 models the position and range of the source of a radio signal. Describe the position of the sour

12345 [234]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2}
\\\\\\
center~(3,-7)\qquad radius=8$

so, the broadcast location and range is more or less like the picture below.