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3 years ago

Somebody please help

Mathematics

1 answer:

DedPeter [7]3 years ago

6 0

Answer:

169

Step-by-step explanation:

13²

=169

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If ∆ABC = ∆EDF where the coordinates of A(0,2), B(2,4), and C(2,-1), what is the measure of DF?A-3B-3.1C-5D-5.9Please respond qu

aev [14]

The triangles ABC and EDF are congruent, meaning they have the same side lengths and angles measures.

The measure of DF, as both triangles are congruent, is equal to the measure of BC.

We can calculate the length of BC using the distance formula:

$\begin{gathered} D=\sqrt[]{(x_c-x_b)^2+(y_c-y_b_{})^2} \\ D=\sqrt[]{(2-2)^2+(-1-4)^2} \\ D=\sqrt[]{0^2+(-5)^2} \\ D=\sqrt[]{(-5)^2} \\ D=|-5| \\ D=5 \end{gathered}$

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1 year ago

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inn [45]

Answer:

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Step-by-step explanation:

In the picture attached, the complete question is shown.

The expression is:

$\frac{ \frac{1}{2} }{ \frac{-2}{5}} + \frac{-1}{4}$

You can rewrite the first term, expressing the division as a multiplication, that is, inverting the fraction in the denominator, as follows:

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