The answer to your question is 10 pints because pints in general are bigger than cups even If it's 20 cups
        
                    
             
        
        
        
The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
 After that you have to <span>subtract and (x) from every each zero that you have above, which means 
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<span>And the last step is to multiply them together, and that's all you need! 
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<span>I am pretty sure that everything hase become clear! Regards.</span>
 
        
        
        
Answer:
Tn = 2Tn-1 - Tn-2 
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
 If a17 = -40 
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
 (Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2 
The recursive formula will be 
Tn = 2Tn-1 - Tn-2 
 
        
                    
             
        
        
        
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