All categories

2 years ago

-8= t/27 t=??????????

Mathematics

1 answer:

Andreyy892 years ago

5 0

Answer:

t = -216

Step-by-step explanation:

-8 = t/27

Multiply both sides by 27

-216 = t

You might be interested in

If you multiply a number by 3 and then subtract 5, you will get 40. What is the number?

evablogger [386]

Answer:

Step-by-step explanation:

Solve the problem backwards and it gives you the answer. Hope this helps

3 0

2 years ago

i am a 2 dimensional shape that has four sides. I have four 90 degree angles.i have two sets of parallel lines. i also have two

Roman55 [17]

The answer is 190 for u'r information

6 0

2 years ago

Read 2 more answers

Match The Following, 26 POINTS HELP FAST

zavuch27 [327]

The formula for the volume of a cone is:

$1/3\pi r^{2} h$

The formula for the volume of a cylinder is:

$\pi r^2h$

The formula for the volume of a triangular prism is:

$bh$

The formula for the volume of a pyramid is:

$1/3bh$

The formula for the volume of a rectangular prism is:

$lwh$

6 0

2 years ago

Read 2 more answers

Which expression are equivalent to 2x+4

Ksivusya [100]

Answer:

2(x+2)

Step-by-step explanation:

Factor out the 2.

4 0

2 years ago

39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$

4 0

1 year ago