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2 years ago

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Aiden says that the shape below is a rectangle. Parallelogram Part A Is Aiden correct? Use the drop-down menus to show your answ

er. Choose... , the shape Choose... a rectangle

1 answer:

ElenaW [278]2 years ago

8 0

Need to see the image

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What is the rate of 78 and 2

NeTakaya

78/2
= 39 is the answer

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3 years ago

A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a)

Alla [95]

Answer:

A(t) = 90e^0.12t ;

299 mg

Step-by-step explanation:

General Continous growth rate equation :

A = Pe^rt

A = amount present, t years after year of initial amount.

Here,

P = 90 mg, amount in year 2000

r = rate = 12% = 0.12

t = years after 2000

Therefore,

A is written as ;

A(t) = 90e^0.12t

Amount present in year 2010 ;

t = 2010 - 2000 = 10

A(10) = 90e^0.12(10)

A(10) = 90 * e^1.2

= 90 * 3.3201169

= 298.81052

= 299 mg

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2 years ago

Find the derivative of the function. y = sin−1(6x + 1)

liraira [26]

If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:

$y=\sin^{-1}(6x+1)\implies\sin y=6x+1$

(true for <em>y</em> between -π/2 and π/2)

Now take the derivative of both sides and solve for it:

$\cos y\dfrac{\mathrm dy}{\mathrm dx}=6$

$\dfrac{\mathrm dy}{\mathrm dx}=6\sec y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\cos\left(\sin^{-1}(6x+1)\right)}$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\sqrt{1-(6x+1)^2}}$

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3 years ago

6cos(20πt-π)+6√3cos(20πt-π\2)

juin [17]

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

Step-by-step explanation:

${ \tt{ = (6 \cos(20\pi t) \cos(\pi) + 6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t) \cos( \frac{\pi}{2} ) + \sin(20\pi t) \sin( \frac{\pi}{2} )) }} \\ = { \tt{ (- 6t + 0) + (0 + 0)}} \\ = { \tt{ - 6t}}$

Note that π is 180°

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2 years ago

Uhh i need help please...

marishachu [46]

With what? what’s the question

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2 years ago

Read 2 more answers