If F(x) = 2x-3/5 which of the following is the inverse of F(x)?
1 answer:
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Answer:
1 and 6
Step-by-step explanation:
it is just like the roots of a polynomial, since (x-6)^2=0
we can separate the two pieces of the problem
\sqrt{x-1} =0
square both sides to get
x-1=0. x=1
(x-6)^2=0
square root both sides and get
x-6=0
x=6
so the two inflection points of the equation are 6 and 1
Hope that helps :)
Answer:
- modulus: 3√2
- argument: -3π/4 (or 5π/4)
Step-by-step explanation:
The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).
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<h3>rectangular form</h3>The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:
The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:
modulus = √((-3)² +(-3)²) = 3√2
The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.
arg = arctan(-3/-3) = -3π/4 or 5π/4 . . . . radians
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modulus∠argument = (3√2)∠(-3π/4)