Laura deposits $10,000 into an account that compounds interest continuously

Mathematics

1 answer:

julia-pushkina [17]2 years ago

5 0

Answer:15.5 because you have to take away some point

Step-by-step explanation:

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Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,

Kazeer [188]

Answer: 2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula $A=A_oe^{kt}$ where

A is the final amount (amount left)
A₀ is the initial amount (amount you started with)
k is the rate of decay (you need to solve for this)
t is the time

Given:

A = 1/2(300) = 150
A₀ = 300
k = unknown
t = 28.8

$150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\$

Next, input the k-value and the new t-value to solve for A.

A = unknown
A₀ = 300
k = -0.0240676
t = 1440

$A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\$

5 0

3 years ago

Show work to above problem

Len [333]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
|a|\implies 
\begin{cases}
+a\\
-a
\end{cases}\implies \pm a\\\\
-------------------------------\\\\
(16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x
\\\\\\
\begin{cases}
+4\\
-4
\end{cases}\implies |4x|$