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harkovskaia [24]
3 years ago
14

free 100 pointssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

ssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0
You are very cool person
Katarina [22]3 years ago
4 0

Answer:

Thank you for the points man I really need them to ask a huge question

Step-by-step explanation:

I answer your question, I get the points, I make the question, someone elce gets the points.

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(Please show your work) (1 kwh = 3400 BTU’s 1 gallon = 8 pounds of water) The water coming into a dishwasher from a water heater
shtirl [24]

Answer:

5700 BTU

Step-by-step explanation:

Data provided in the question:

1 kwh = 3400 BTU’s

1 gallon = 8 pounds of water

Initial temperature = 50°F

Final temperature = 100°F

Water used by dishwasher = 10 gallons

Electrical energy used = 0.5 kwh

Now,

Water used in pounds = 10 × 8 = 80 lb

Total electrical energy used in BTU = 0.5 × 3400 BTU     [ as 1 kwh = 3400 BTU]

Total electrical energy used in BTU = 1700 BTU

Energy used by water = Water used by dishwasher × Change in temperature × Specific heat of water

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Thus,

Energy used by water = 80 × 1 × ( 100 - 50 )

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Total energy used = 1700 BTU + 4000 BTU = 5700 BTU

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