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jenyasd209 [6]
3 years ago
15

NEED HELP

Mathematics
2 answers:
nordsb [41]3 years ago
8 0

Answer:

Open the compass to the length of AB and draw a cirle centered at point A. Without changing the compass opening, draw a circle centered at point B

Step-by-step explanation:

Anvisha [2.4K]3 years ago
7 0

The answer is the fourth option. Put the compass point on A and the pencil point on the segment, closer to point B than to point A, and draw a circle centered at point A. Without changing the compass opening, draw a circle centered at point B. The diagonals of a square bisect each other in mutually perpendicular. Let AB be the diagonal, when we draw a perpendicular to the diagonal AB the other two points of the square are in this perpendicular.And are in opposite sides.So we draw the two circles with same radius less than AB and greater than half of AB.  

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What is the domain and range of the following ordered pairs: {(-6, -7), (-1, 1), (0,
____ [38]

Answer:

The answer is the last option (d.)

Step-by-step explanation:

The domain is the X values and the range is the Y values.

5 0
3 years ago
Okay, I understand this is very easy homework, but I am awarding 25 points, more than most for some pretty simple work. Thanks a
iris [78.8K]

Answer:

No Answers

Step-by-step explanation:

You have yet to provide some kind of questions for us to solve for these promised points.

4 0
4 years ago
Verify the identity. <br><br>cot. (x - (pi/2)) = -tan x<br><br>Please, help me!!!
Leya [2.2K]

Answer:

cot . (x- π/2)= - tanx

Step-by-step explanation:

cot . (x- π/2)= - tanx

cot .x - cot π/2= - tanx

cot π/2= 1/tanπ/2

But tan π/2= ∞

cot π/2 = 1/∞= 0

cotx - 0= - tanx

cot x = - tanx

cosx/sinx= - sinx/cosx             Putting values of cot and tan

cosx/ sinx ( sinx/cos x) = -sinx/cos x  (sinx/cos x )  

Multiplying both sides with  sinx/cos x    

1= - sin²x/cos²x

cos²x= - sin²x                 as cosx = -sinx

5 0
3 years ago
Write a word porblem that could be solved with the equation x - 3/4 = 6 3/4
Amanda [17]

Answer:

use ph0t03ath or m4th3ay

7 0
3 years ago
A. 4x^5+3x+2<br> B. 4x^2+3x+2x^5<br> C. 4x^5+3+2/x^5<br> D. 18x^5+12x+6
aalyn [17]
The answer is C. 4x^5 + 3 + 2/x^5
3 0
3 years ago
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