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3 years ago

Select the scenario below that demonstrates sampling error. Select the correct answer below:

Mathematics

1 answer:

UNO [17]3 years ago

7 0

Answer:

e. An online retailer reaches out only to its customers who have left positive reviews for its product and asks them to complete a survey of their experience with the retailer's products

Step-by-step explanation:

A sampling error happens when a sample has some kind of a bias.

One example is for example, sampling only members of one political party about a new bill.

In this question:

The correct answer is given by option e, because the retailer will have the opinions only from those with positive reviews, basically disconsidering those with negative reviews, and not giving them a clear idea of their service.

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The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 2135 miles, with a variance

stiv31 [10]

Answer:

0.36878

Step-by-step explanation:

Given that:

Mean number of miles (m) = 2135 miles

Variance = 145924

Sample size (n) = 40

Standard deviation (s) = √variance = √145924 = 382

probability that the mean of a sample of 40 cars would differ from the population mean by less than 29 miles

P( 2135 - 29 < z < 2135 + 29)

Z = (x - m) / s /√n

Z = [(2106 - 2135) / 382 / √40] < z < [(2164 - 2135) / 382 / √40]

Z = (- 29 / 60.399503) < z < (29 / 60.399503)

Z = - 0.4801364 < z < 0.4801364

P(Z < - 0.48) = 0.31561

P(Z < - 0.48) = 0.68439

P(- 0.480 < z < 0.480) = 0.68439 - 0.31561 = 0.36878

= 0.36878

3 0

2 years ago

Х<br> 1<br> 2<br> 3<br> 4<br> Y<br> 5<br> 9<br> 13<br> 17

serious [3.7K]

What’s your question?

4 0

3 years ago

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

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3 0

2 years ago

One x-intercept for a parabola is at the point (4,0). Find the other x-intercept for the parabola defined by this equation y=x^2

yanalaym [24]

Probably the easiest way to do this is to use synthetic division. We already know one of the zeros of the quadratic so we can use that number to find the other zero. If the point is (4, 0), then when y = 0, x = 4. Thus, 4 is a zero. Put 4 outside the "box" and put the coefficients from the quadratic inside, like this: 4 (1 -1 -12). Draw a line and bring down the first one under it. Multiply that 1 by the 4 to get 4. Put that 4 up under the -1 and add to get 3. Multiply 3 by 4 to get 12. Put that 12 up under the -12 and add to get 0. The numbers left under the line are the coefficients for the next polynomial, called the depressed polynomial, and this polyomial is one degree less than the one we started with. Those coefficients are 1 and 3. Therefore, the polynomial is x + 3 = 0. That means that the other zero, or x-intercept, is x = -3.

6 0

3 years ago

Can somebody please help me with this

dsp73

Suggestion: Please show the problem for the questions, or I'm afraid I can't help!

8 0

3 years ago