In a trapezoid, the segment at the midpoint is the average of the other two bases.
In other words: YZ = (QR + TS) / 2
5x + 1 = ( (2x + 7) + 19 ) / 2
2(5x + 1) = 2x + 26
10x + 2 = 2x + 26
8x = 24
x = 3
YZ = 5x + 1
YZ = 5(3) + 1
YZ = 15 + 1
YZ = 16
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a) C(0.5) = 39, C(2) = 39, C(4) = 69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5) = 39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2) = 39
Since x = 4 is in the range x > 2
C(4) = 39 + 15(x - 2)
C(4) = 39 + 15 (4 - 2)
C(4) = 39 + 15(2)
C(4) = 39 + 30
C(4) = 69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2) = 39

Since
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
Answer:
375< y < 525
Step-by-step explanation:
The minimum is 15* 25 = 375
the maximum is 15 * 35 =525
He can earn any amount between these two values
Answer:
10ibs=1000% 6ibs=600%
Step-by-step explanation: